A solution contain substances A and B in H,O(solvent). The mole fraction of 'A' is 0.05 andmolarity of 'B' is 7 M. The solution has density1.14 gm/ml. Calculate "molarity of A".[Molecular weight of A = 10 gm/mol; molecularweight of B = 30 gm/mol]
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Answer:
The answer is 0.88 M
Explanation:
Mole fraction of A, Xa = nA/nT= 0.05 = 5/100
It means 5 moles of A are present in 100 molesw of solution.
Thus
nA + nB + H2O = 100
Let's suppose water is 100 ml
So no of moles of water is nH2O= 100/18 = 55.55 mol
nB = 100 - 55.55 - 5 = 39.45 mol
Now find the volume of solution.
The volume of solution = Moles of B / 7 = 39.45/7
= 5.63 L
Molarity of A = 5/5.63 = 0.88 M
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