Math, asked by shekhawatrailway, 8 months ago

A solution contain wine and water in ratio 2:1 Out of it 36 litre solution is replaced by 15 litre water. Again 26 litre solution is replaced by same quality of water. Now wine water ratio become 8:7 Find difference between water quantity in initial and final solution.​

Answers

Answered by amitnrw
5

Given : A solution contain wine and water in ratio 2:1 Out of it 36 litre solution is replaced by 15 litre water. Again 26 litre solution is replaced by same quality of water. Now wine water ratio become 8:7

To find : difference between water quantity in initial and final solution.​

Solution:

Let Say

Wine   = 2A  Litre

Water   = A   Litre

Total Solution = 3A  Litre

36 litre solution is replaced by 15 litre water.

=> Wine =  2A  - (2/3)36  = 2A - 24 Litre

Water = A  - (1/3)36 = A - 12 + 15  =  A + 3  Litre

Wine = 2(A - 12)

Water = A + 3

=> Total = 3A - 21 = 3(A - 7)

now 26 litre Solution is replaced by water

Wine = 2(A - 12)  -  26*2(A - 12)/3(A - 7)  =   (6A² -114A + 504  -52A  + 624)/3(A - 7)

=> Water   = A + 3    -   26(A + 3)/3(A - 7)   + 26 =  (3A² + 66A  - 609 -26A - 78)/3(A - 7)

=>  (6A² -166A + 1128)/( (3A² + 40A  - 687)  = 8/7

=>  (3A² -83A + 564)/( (3A² + 40A  - 687)  = 4/7

=> 21A² - 581A + 3948  = 12A² + 160A   -  2748

=> 9A²  - 741A  + 6696 = 0

=> 3A² - 247A + 2232 =0

=> 3A² - 216A  - 31A + 2232 =0

=> 3A(A - 72) -31(A - 72) = 0

=> (3A - 31) (A - 72) = 0

=> A = 31/3   or A = 72

A = 31/3 not possible as then totaol solution initially = 31 litre while 36 litre taken out

Hence

A = 72

Water in initial  = 72

Water in Final  = A + 3    -   26(A + 3)/3(A - 7)   + 26  putting A = 72   = 91

Water in Final = 91    

Difference = 91 - 72 = 19

difference between water quantity in initial and final solution.​ = 19 Litre

Wine Water Total

144        72          216

120  75           195

104  91           195

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