Question

A solution contained Na 2
​ CO 3
​ and NaHCO 3
​ . 15 ml of the solution required 5 ml of 10
N
​ HCl for neutralization using phenolphthalein as an indicator. Addition of methyl orange required a further 15 ml of the acid for neutralization. The amount of Na 2
​ CO 3
​ present in the solution is:

Answer 1

Answer:

Na2

n(Na2)= 15/22,4

=0,67 mol

n(Na2)=m/M

0,67=m/46

m=30,82 g