A solution containing 0.2 moles of ferric chloride is allowed to react with 0.24 moles of sodium hydroxide. The correct statement (s) for this reaction is
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The reaction is \(FeCl_3 + 3NaOH \rightarrow Fe(OH)_3+3NaCl\). Thus, \(1\) mole of ferric chloride will react with \(3\) moles of \(NaOH\) to form one mole of ferric hydroxide. ... The unreacted amount of ferric chloride is \(0.2-0.08=0.12\) moles.
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