a solution containing 1.20 gram of an organic solute per 50 gram of ccl4 boils at 350.5 Kelvin under atmospheric pressure . what is the molecular mass of the solute ? normal boiling point of ccl4 is 350 Kelvin and KB value is 5.0 Kelvin. Kg per mole ?
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Given:
w = 1.2 gm
W = 50 gm
Tb = 350 K
Tb' = 350.5 K
Kb = 5 K kg/mol
To Find:
Molecular weight of the solid.
Calculation:
- We know that the elevation in boiling point is given as:
ΔTb = Kb × m
⇒ (Tb' - Tb) = Kb × (w × 1000)/(M.wt × W)
⇒ (350.5 - 350) = 5 × (1.2 × 1000)/(M.wt × 50)
⇒ 0.5 = 5 × (1.2 × 20)/ M.wt
⇒ M.wt = 120/0.5
⇒ M.wt = 240 gm
- So, the molecular mass of the solute is 240 gm.
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