Chemistry, asked by neelareddyyarrapared, 3 months ago

A solution containing 1.23 g of Ca(NO3)2 in
10 g of water a normal boiling point of
100.975°C. The degree of dissociation of
Ca(NO3)2 will be: (Kb, water = 0.52 k kg mot
1) (Ca = 40; N = 40; N= 14,0 = 16)
O 0.25
O 0.33
0.5
0.75​

Answers

Answered by jayantkumargodda1234
0

Answer:

0.75

Explanation:

  1. hope this will help full
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