Question

A solution containing 10 g/l of sucrose as an osmotic pressure of 0.66 at atm at temperature 273k . calculate the value of the constant R

Answer 1

10g sucrose contains 1L of solution .

weight of sucrose in 1L = 10g

molecular weight of sucrose ,(C₁₂H₂₂O₁₁) = 342 g/mol

∴ mole of sucrose = 10/342 = 0.02923

so, concentration of sucrose in solution = 0.02923mol/1L = 0.02923 M

we know, Osmotic pressure , π = CRT

here C is concentration, R is universal gas constant and T is temperature in Kelvin.

Given, C = 0.02923M , π = 0.66 atm and T = 273K

Now, R = π/CT = 0.66/0.02923 × 273 = 0.08270 atm.L/mol/K

Hence, R = 0.08270 atm.L/mol/K

Answer 2

hi friends....

your answer given below........

10g sucrose contains 1L of solution .

weight of sucrose in 1L = 10g

molecular weight of sucrose ,(C₁₂H₂₂O₁₁) = 342 g/mol

∴ mole of sucrose = 10/342 = 0.02923

so, concentration of sucrose in solution = 0.02923mol/1L = 0.02923 M

we know, Osmotic pressure , π = CRT

here C is concentration, R is universal gas constant and T is temperature in Kelvin.

Given, C = 0.02923M , π = 0.66 atm and T = 273K

Now, R = π/CT = 0.66/0.02923 × 273 = 0.08270 atm.L/mol/K

Hence, R = 0.08270 atm.L/mol/K.

hope it helps !