Chemistry, asked by Anonymous, 1 year ago

A solution containing 12.0% sodium Hydroxide by mass has a density of 1.131 g/ml . What volume of this solution contains 5.00 mol of NaOH

Answers

Answered by parisakura98pari
16
let's  assume 12% implies 12gm of NaOH  in 100gm of solution
density of solution = 1.131gm/ml
therefore volume of solution = weight of solution / density of solution =12/1.131= 10.61 ml

no of moles of NaOH = weight of NaOH / molar mass of NaOH = 12/40 =0.3

therefore 0.3 mol in 10.61 ml of solution

morality = no of moles / volume of solution = 0.3/10.61 = 0.028
now A/Q vol of solution having 5 mol = 5/0.028 = 178.57ml

hope my answer is right

if any queries please ask

Anonymous: That Is the wrong answer
Anonymous: If u dont know then dont answer
parisakura98pari: its all right ...why to panic .I tried my best....I'll recheck my ans
Anonymous: ok
parisakura98pari: hey.....I took wt of soln to b 12 gm instead of 100 gm..is ans 1474.925ml.......... please check
Anonymous: nope
parisakura98pari: it should b .........whats the actual ans?
SahilBaori: The answer 1474.92 is correct...
SahilBaori: you stupid.....
Answered by shreyankanvinde
8

Answer:1.47L

Explanation:

12gm(12/40 moles) of NaOH present in 100gm soln.

So 1 mole is present in (100×40)/12 = 333.34gm

Thus 5moles are present in 333.34×5=1666.6g

Now, density=mass/volume

Here d=1.131g/ml=1131g/L

Thus volume = 1666.6/1131 = 1.47L

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