A solution containing 12.3 g of
calcium nitrate in 100 g of water boils
at 373.98 K. Find the degree of
dissociation of calcium nitrate.
Answers
Answered by
0
Answer:
Given - 1.23 g of Ca(NO
3
)
2
in 10 g of H
2
O. K
b
=0.52
We know that, K
b
=Cα
2
α - Degree of Dissociation C - Molarity / Molality
C =
164
1.24
×
10
1000
= 0.75
K
b
=Cα
2
⇒α=
C
K
b
=
0.75
0.52
=
0.69
=0.83
Hence the degree of dissociation is 0.83
Answered by
0
Explanation:
Given - 1.23 g of Ca(NO
3
)
2
in 10 g of H
2
O. K
b
=0.52
We know that, K
b
=Cα
2
α - Degree of Dissociation C - Molarity / Molality
C =
164
1.24
×
10
1000
= 0.75
K
b
=Cα
2
⇒α=
C
K
b
=
0.75
0.52
=
0.69
=0.83
Hence the degree of dissociation is 0.83 .
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