Question

A solution containing 12.3 g of
calcium nitrate in 100 g of water boils
at 373.98 K. Find the degree of

dissociation of calcium nitrate.​

Answer 1

Answer:

Given - 1.23 g of Ca(NO

3

)

2

in 10 g of H

2

O. K

b

=0.52

We know that, K

b

=Cα

2

α - Degree of Dissociation C - Molarity / Molality

C =

164

1.24

×

10

1000

= 0.75

K

b

=Cα

2

⇒α=

C

K

b

=

0.75

0.52

=

0.69

=0.83

Hence the degree of dissociation is 0.83

Answer 2

Explanation:

Given - 1.23 g of Ca(NO

3

)

2

in 10 g of H

2

O. K

b

=0.52

We know that, K

b

=Cα

2

α - Degree of Dissociation C - Molarity / Molality

C =

164

1.24

×

10

1000

= 0.75

K

b

=Cα

2

⇒α=

C

K

b

=

0.75

0.52

=

0.69

=0.83

Hence the degree of dissociation is 0.83 .

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