Question

a solution containing 13.5 gram urea per 500 ml of solution in water has same osmotic pressure as a solution of sucrose in water calculate the mass of sucrose present in 500 ml of its solution

Answer 1

Answer:

The mass of sucrose is 77g  

Explanation:

From the given,

Weight of Urea = 13.5 g

Volume of urea = 500 ml

Molar mass of urea = 60 g/mol

Volume of sucrose = 500 ml

Molar mass of sucrose = 342.3 g/mol

If the solutions have same somatic pressure called isotonic solutions.

From the given, water and sucrose has same osmotic pressure hence they are called as isotonic solutions.

For isotonic solutions,

$\pi_{1}=\pi_{2}$

At same pressure $\mathrm{C}_{1}=\mathrm{C}_{2}$

At same volume $\mathrm{n}_{1}=\mathrm{n}_{2}$

$\frac{13.5}{60}=\frac{x}{342.3}$

$\mathrm{x}=\frac{13.5 \times 342.3}{60}$

=77 g

Therefore, mass of sucrose is 77g

Answer 2

Answer:

Explanation:

The mass of sucrose is 77g

Explanation:

From the given,

Weight of Urea = 13.5 g

Volume of urea = 500 ml

Molar mass of urea = 60 g/mol

Volume of sucrose = 500 ml

Molar mass of sucrose = 342.3 g/mol

If the solutions have same somatic pressure called isotonic solutions.

From the given, water and sucrose has same osmotic pressure hence they are called as isotonic solutions.