Question

A solution containing 2.5 gms of a solute disolved in 80 gm water boils at 101degree celsius calculate molecular weight of solute​

Answer 1

Answer:

hey mate

Explanation:

Let M be the molecular weight of solute.

The number of moles is the ratio of mass to molecular weight.

Number of moles of solute =

M

3.24

The molality of solution is the number of moles of solute in 1000 g of water.

Molality =m=

M×200

3.24×1000

=

M

16.2

Elevation in the boiling point =ΔT

b

=100.130−100=0.130

o

C

ΔT

b

=K

b

m

0.130=0.513×

M

16.2

M=

0.130

0.513×16.2

=64g/mol..

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