Question

A solution containing 200 mL of 0.5 M BaCl2 and 400 mL of 0.5 M H2SO4 are mixed and diluted to 1000 mL. The volume of 0.1 M Ba(OH)2 required to neutralise 100 mL of above (diluted) solution is

Answer 1

Answer:

200 × 0.5 = 100

400 × 0.5 = 200

1000× 0.1 = 100

so 200 - 100 is 100

Answer 2

200ML WILL BE THE FINAL ANSWER

Milliequivalents of H+ = milli equivalents of Ba(OH)2 for complete neutralisation
40=2*0.1*V
V= 200mL
This is the final answer
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