A solution containing 200 mL of 0.5 M BaCl2 and 400 mL of 0.5 M H2SO4 are mixed and diluted to 1000 mL. The volume of 0.1 M Ba(OH)2 required to neutralise 100 mL of above (diluted) solution is
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Answer:
200 × 0.5 = 100
400 × 0.5 = 200
1000× 0.1 = 100
so 200 - 100 is 100
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1
200ML WILL BE THE FINAL ANSWER
Milliequivalents of H+ = milli equivalents of Ba(OH)2 for complete neutralisation
40=2*0.1*V
V= 200mL
This is the final answer
Hope my answer helps you :)
Please mark this as the brainleist answer
Milliequivalents of H+ = milli equivalents of Ba(OH)2 for complete neutralisation
40=2*0.1*V
V= 200mL
This is the final answer
Hope my answer helps you :)
Please mark this as the brainleist answer
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