Question

a solution containing 32 gm of ammonium chloride in 160 g of the solution. What is mass by mass percentage of the solution​

Answer 1

Given:

A solution containing 32 gm of ammonium chloride in 160 g of the solution.

To find:

Mass by mass (m/m) % of the solution.

Calculation:

General expression for mass by mass percentage strength of a solution is given as follows:

$\boxed{ \bf{(m/ m) \%= \dfrac{mass \: of \: solute}{mass \: of \: solution} \times 100\%}}$

So, putting the available values:

$= > \rm{(m/ m) \%= \dfrac{32}{160} \times 100\%}$

$= > \rm{(m/ m) \%= 0.2\times 100\%}$

$= > \rm{(m/ m) \%= 20\%}$

So, final answer is:

$\boxed{\bf{(m/ m) \%= 20\%}}$

• (m/m)% is a better index of strength of a solution than (m/v)% because mass of the solute and the mass of solvent is independent of temperature of the surroundings.