Question

A solution containing 34.2g per dm^3 of sucrose(molar mass=342 g mol^-1) is isotonic with 15% (w/v) solution of non volatile and non electrolyte solute at same temperature . the molar mass of solute is:

A) 750 g/mol
B) 1500 g/mol
C) 150 g/mol
D) 300g/mol

Answer 1

Answer:

option a is the answer

Explanation:

Answer 2

Answer:

B) 1500g/mol is the correct answer.

Explanation:

Given : concentration of sucrose= 34.2gm/$dm^3$ = $=34.2gm/1000cm^3 = 34.2gm/L$$= \frac{34.2}{342} mol/L=0.1mol/L$

Let molar mass of solute is $m$.

concentration of solute = 15% = $\frac{15gm}{100cm^3}=\frac{150gm}{1000cm^3}=150gm/L = \frac{150}{m} mol/L$

As, solution is given  isotonic

$\implies$ concentration of sucrose = concentration of solute

$\implies 0.1 mol/L=\frac{150}{m} mol/L$

$\implies m = \frac{150}{0.1} =1500gm$

The molar mass of solute is 1500gm.

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