Physics, asked by pavibalam20, 11 hours ago

A solution containing 34.2g per dm^3 of sucrose(molar mass=342 g mol^-1) is isotonic with 15% (w/v) solution of non volatile and non electrolyte solute at same temperature . the molar mass of solute is:

A) 750 g/mol
B) 1500 g/mol
C) 150 g/mol
D) 300g/mol

Answers

Answered by abhisheksuresh208
7

Answer:

option a is the answer

Explanation:

Answered by vaibhavsemwal
1

Answer:

B) 1500g/mol is the correct answer.

Explanation:

Given : concentration of sucrose= 34.2gm/dm^3 = =34.2gm/1000cm^3 = 34.2gm/L= \frac{34.2}{342} mol/L=0.1mol/L

Let molar mass of solute is m.

concentration of solute = 15% = \frac{15gm}{100cm^3}=\frac{150gm}{1000cm^3}=150gm/L = \frac{150}{m} mol/L

As, solution is given  isotonic

\implies concentration of sucrose = concentration of solute

\implies 0.1 mol/L=\frac{150}{m} mol/L

\implies m = \frac{150}{0.1} =1500gm

The molar mass of solute is 1500gm.

#SPJ3

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