A solution containing 45 ml of acid and 60 ml of water is completely mixed with another solution E which contains 711711 of acid. If the proportion of acid and water in the final mixture is equal, find the quantity of solution E.
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Answer:hey dear
Let the quantity of solution E be x ml.
Amount of acid in final mixture = (45 + 7x/11) ml
Amount of water in final mixture = (60 + 4x/11) ml
Now, (45 + 7x/11) = (60 + 4x/11)
=> x = 55 ml
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