Chemistry, asked by aanchaldhiman8999, 1 year ago

A solution containing 6g of benzoic acid in 50g of ether (c2h5oc2h5) has vapour pressure of 410mm of mercury at 293 kelvin given the vapour pressure of ether at same temperature is 442mm of mercury calculate the molecular mass of benzoic acid (assume the solution to be dilute)

Answers

Answered by IlaMends
11

Answer:

The molecular mass of benzoic acid is 123.53 g/mol.

Explanation:

Vapor pressure of pure ether,p_o = 442 mmHg

Vapor pressure of the solution ,p_s= 410 mmHg

Mass of solute that is benzoic acid = w_2=6g

molar mass of benzoic acid = M_2

Mass of solvent =w_1=50 g

molar mass of ether = M_1=74.12 g.mol

The relation between the molecular masses and pressures :

\frac{(p_o-p_s)}{p_o}=\frac{w_2\times m_1}{w_1\times M_2}

\frac{442mmHg-410 mmHg}{442 mmHg}=0.07=\frac{6g\times 74.12 g/mol}{50 g\times M_2}

M_2=123.53 g.mol

The molecular mass of benzoic acid  is 123.53 g/mol.

Answered by amandeep45458
11

Explanation:

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