Question

A Solution contains 1.2046×10^24 hydrochloric acid molecules in one dm^3 of the solution . The strength of solution is..????

Answer 1

Answer: 2 N

Explanation:

M = (N/NₐV)

N is the number of molecules present in the volume V (in litres),

Nₐ is the Avogadro constant, nearly 6.022 × 10²³ mol⁻¹

Or simply: 1 molar = 1 M = 1 mole/litre.

M = (N/NₐV) = (1.2046 x 10²⁴)/(6.022 x 10²³ x 1) = 12.046/6.022 = 2 M

(As , 1 dm³ = 1 L)

For HCl, equivalent weight = molecular weight, hence, molarity = normality

Therefore, the strength of the solution is = 2 N