Question

A solution contains 1.82 g of glucose and 25g of water.calculate molality and mole fraction of glucose and water.

Answer 1

No. of moles of glucose=mass/molarmass
=1.82/180=0.01
Molality=0.01 * 1000/25=0.4
No. of moles of water=25/18=1.3
Mole fraction of glucose=0.4/0.4+1.3=0.23
Mole
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fractio of water=1.3/0.4+1.3=0.76