Question

A solution contains 10 ml 0.1 n naoh and 10 ml 0.05 n h2so4, ph of this solution is

Answer 1

Answer:

Well the solution will go like this.

Before neutralization.

Millimoles of HCl =50x0.4=20

Millimoles of NaOH= 50x0.2=10

After neutralization,

Millimoles of NaOH=0

Millimoles of HCl=10 (by the concept of limiting reagent)

HCl will get dissociated into H+ and Cl-

Now concentration of H+ = 10/100=0.1M (the solution becomes 100 ml)

SO by the formula

pH=-log[H+]

we will get pH= 1

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