Question

A solution contains 10 moles of salt in 1 kg of solvent. Calculate the molality of solution.​

Answer 1

Answer:

Explanation:

nA=10 moles

Amount of solvent=1 kg

m=nA/Amount of solvent(in kg)

m=10moles/kg=10m

Answer 2

Explanation:

$molality(m) = \\ \frac{no.of \: moles \: of \: solute}{kg \: of \: solvent}$

$= \frac{10mol}{1kg } = 10mol \: {kg}^{ - 1}$✔

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