Question

A solution contains 10g of ethanol dissolved in 200ml of water calculate the concentration in terms of volume percentage

Answer 1

Solution

$\Large{\sf{\green{4.76\%}}}$

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$\sf{Given}\begin{cases}\sf{\green{Mass\:of\:solute = 10\:g}}\\</p><p>\sf{\green{Volume\:of\:solvent = 200\:mL}}\\</p><p>\end{cases}</p><p>$

$\sf{\underline{\underline{\green{To\:find}}}}\\</p><p>\sf {\bigstar\: Volume\: percentage}\\</p><p>$

$\sf{\underline{\underline{\green{Converting\:g\: \longrightarrow\: ml}}}}\\</p><p>\sf {\bigstar\:10\: g \: \longrightarrow\: 10\:ml}\\ \\</p><p>\boxed{\sf{\purple{Volume_{\:solution} = Volume_{\:solute} + Volume_{\:solvent}}}}\\</p><p>\sf{\implies\: Volume_{\:solution} = 10\:mL + 200\:mL}\\</p><p>\sf{\implies\: Volume_{\: solution} = 210\:mL}\\ \\</p><p>$

$\boxed{\sf{\red{Volume\:percentage = \frac{Volume_{\:solute}}{Volume_{\:solution}} × 100}}}$

$\sf{\implies\: Volume\:percentage = \frac{10\: \cancel{ml}}{210\: \cancel{ml}} × 100}$

$\sf{\implies\:Volume\:percentage = 4.76\% \: \:(\green{Answer})}\\ \\</p><p>$

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Note:

$\sf{\bigstar\: 1g = 1\:mL}$

$\sf{\bigstar\: 1g = 10^{-3}\:L}$