A solution contains 1450 g of copper sulphate in 4.5 kg of water. Calculate the concentration in terms of mass by mass percentage of the solution. If the amount of water is changed to 2000 ml, what will be the difference in the concentration of the solution?
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Explanation:
mass by mass percent of solution=
(mass of copper sulphate / total mass of solution )× 100
=(1450/4500+1450)×100
=(1450/5950)×100
=24.3%
If the amount of water is changed to 2000ml
concentration= mass of copper sulphate/ volume of solution in dm³
= 1450/2
= 725 M
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