A solution contains 15g urea (molar mass =60g mol^-1)per liter of solution in water has the same osmotic pressure as a solution of glucose(molar mass =180g mol^-1)in water .calculate the mass of glucose present in one litre of its solution.
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45g
Explanation:
First we need to calculate No. of moles of urea.
= 15/60
= 0.25 mol
Hence it is in 1L of solution 0.25 is the molarity.
Osmotic pressure is equal and as per the theory their molarities will also be equal.
So, 0.25 = No. of moles of glucose/1 (Because, volume is 1L)
ie. we now got the moles and it's easy to find the mass by:
0.25 = mass of glucose/Molar mass
ie. mass of glucose = 0.25 * 180 (Molar mass is in the question)
=> 45g
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