Question

a solution contains 2.82 g of glucose molar mass 180 and 30 g of water calculate mole fraction of glucose and water ​

Answer 1

Answer:

We know that,

The weight of glucose=2.82g

Also,

no. of moles of glucose=n

2

=

180

2.82

=0.01567

no. of moles of N

2

O=n

1

=

18

30

=1.667

Molality=

n

1

n

2

×

m.wtofsolvent

1000

=

1.667

0.01567

×

18

1000

=0.5222molal

We have moles of glucose (x

2

)=0.01567

moles of H

2

O(x

1

)=1.667

So, mole fraction of glucose

x

2

=

n

1

+n

2

n

2

=

(1.667+0.01567)

0.0157

=0.0093

mole fraction of H

2

O=x

1

x

1

=1−x

2

=1=0.0093

x

1

=0.9907

Answer 2

Answer:

Let's check what's ur question:solution contains 2.82 g of glucose molar mass 180 and 30 g of water calculate mole fraction of glucose and water

Solution contains glucose C6H12O6 and water

Explanation:

Molar mass of glucose = 180 g

Molar mass of water= 18 g

mole fraction of glucose = moles of glucose/(moles of gluocose+moles of water)

moles of gluocose, n=mass/molar mass=

2.82/180=0.016

moles of water, n=mass/molar mass=30/18=1.67

mole fraction of glucose

=0.016/(0.016+1.67)=0.9907

Hope it helps have a great day