Question

a solution contains 20 g of sugar in 80 g of water. calculate the concentration of solution in terms of mass*mass percent

Answer 1

According to the question,
Mass of solute  ( sugar )  = 20 g
Mass of solvent ( water )  = 80 g
Mass of the solution = Mass of solute + Mass of solvent = 36 + 100 = 136 g
We know,
Concentration of solution = 
Mass of solute / (Mass of solute + Mass of solvent) X 100
= {20 / ( 20+80 )} X 100
= (20 / 100) x 100
= 20 %
Thus, the concentration of this sugar solution is 20 % ( by Mass )

Answer 2

According to the question,

Mass of solute  ( sugar )  = 20 g

Mass of solvent ( water )  = 80 g

Mass of the solution = Mass of solute + Mass of solvent = 36 + 100 = 136 g

We know,

Concentration of solution = 

Mass of solute / (Mass of solute + Mass of solvent) X 100

= {20 / ( 20+80 )} X 100

= (20 / 100) x 100

= 20 %

Thus, the concentration of this sugar solution is 20 % ( by Mass )

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