Chemistry, asked by punamtrivedi11, 10 months ago

a solution contains 20ml methanol,30ml ethanol,and 50 ml of acetone what is the volume percentage of each constituent

Answers

Answered by mukulisonfire
4

Answer:

Volume Percentage of:

Methanol = 20%

Ethanol = 30%

Acetone = 50%

Explanation:

Volume Percentage of each component of solution is given by

    %v/v = (volume of component  ÷ total volume of the solution) × 100

Therefore ,

%v/v methanol = (20/100) X 100% = 20%

Answered by nibha15jan1981
6

Answer:

Hey mate! Here's your answer!!

Explanation:

Given,

Volume of methanol = 20 ml

Volume of ethanol= 30 ml

Volume of acetone = 50 ml

Total volume of the solution = (20+30+50)ml

= 100 ml

-Volume percentage of methanol = 20/100*100

= 20 %

-Volume percentage of ethanol= 30/100*100

= 30%

-Volume percentage of acetone = 50/100*100

= 50 %

HOPE THIS HELPS YA!

HAVE A GREAT DAY!!

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