A solution contains 25% of water 25%of ethanol and 50% of acetic acid. calculate the mole fraction of each component
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Answered by
4
Let us consider the total mass of the solution to be 100 g.
Thus, the mass of water will be 25% of 100 g, i.e. 25 g
Similarly, the mass of ethanol will be 25 g and
the mass of acetic acid will be 50 g.
Let us first calculate the number of moles of each component.
Molarity = Gram Mass / Molar Mass
We know that the molar mass of Water () is 18, that of Ethanol () is 46 and that of Acetic Acid () is 60.
Molarity of Water = 25/18 = 1.388 M
Molarity of Ethanol = 25/46 = 0.543 M
Molarity of Acetic Acid = 50/60 = 0.833 M
We know that Mole Fraction of a particular component =
No. of moles of that component / Total no. of moles of all components in the solution
Total no. of moles = 1.388 + 0.543 + 0.833 = 2.764
Therefore, Mole fraction of Water = 1.388/2.764 = 0.502
Mole fraction of Ethanol = 0.543/2.764 = 0.196
Mole fraction of Acetic Acid = 0.833/2.764 = 0.301
Thus, the mass of water will be 25% of 100 g, i.e. 25 g
Similarly, the mass of ethanol will be 25 g and
the mass of acetic acid will be 50 g.
Let us first calculate the number of moles of each component.
Molarity = Gram Mass / Molar Mass
We know that the molar mass of Water () is 18, that of Ethanol () is 46 and that of Acetic Acid () is 60.
Molarity of Water = 25/18 = 1.388 M
Molarity of Ethanol = 25/46 = 0.543 M
Molarity of Acetic Acid = 50/60 = 0.833 M
We know that Mole Fraction of a particular component =
No. of moles of that component / Total no. of moles of all components in the solution
Total no. of moles = 1.388 + 0.543 + 0.833 = 2.764
Therefore, Mole fraction of Water = 1.388/2.764 = 0.502
Mole fraction of Ethanol = 0.543/2.764 = 0.196
Mole fraction of Acetic Acid = 0.833/2.764 = 0.301
Answered by
2
hlo mate here is ur ans............
Let the mass of solution is 100g
Then, mass of H2O=25g
mass of ethanol =25g
mass of acetic acid =50g
Number of moles of water =25/18g/mol=1.4
Number of moles of ethanol =25/46g/mol=0.54
Number of moles of Acetic acid =50/60g/mol=0.8
Total number of moles =(1.4+0.54+0.8)=2.74
Now, mole fraction of water =1.4/2.74=0.51
mole fraction of Ethanol =0.54/2.74=0.197
mole fraction of acetic acid =0.8/2.74=0.291
hope this helps uh dear :)
pls mark as brainliest..........
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