Chemistry, asked by pgrover5652, 1 year ago

A solution contains 25% of water 25%of ethanol and 50% of acetic acid. calculate the mole fraction of each component

Answers

Answered by ChetanRA
4
Let us consider the total mass of the solution to be 100 g.

Thus, the mass of water will be 25% of 100 g, i.e. 25 g
Similarly, the mass of ethanol will be 25 g and
the mass of acetic acid will be 50 g.

Let us first calculate the number of moles of each component.

Molarity = Gram Mass / Molar Mass

We know that the molar mass of Water ( H_{2} O) is 18, that of Ethanol ( C_{2} H_{5} OH ) is 46 and that of Acetic Acid ( CH_{3} COOH) is 60.

Molarity of Water = 25/18 = 1.388 M
Molarity of Ethanol = 25/46 = 0.543 M
Molarity of Acetic Acid = 50/60 = 0.833 M

We know that Mole Fraction of a particular component = 
No. of moles of that component / Total no. of moles of all components in the solution

Total no. of moles = 1.388 + 0.543 + 0.833 = 2.764

Therefore, Mole fraction of Water = 1.388/2.764 = 0.502
Mole fraction of Ethanol = 0.543/2.764 = 0.196

Mole fraction of Acetic Acid = 0.833/2.764 = 0.301
Answered by meghana1308
2

hlo mate here is ur ans............

Let the mass of solution is 100g

Then, mass of H2​O=25g

    mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water =25/18g/mol​=1.4

Number of moles of ethanol =25/46g/mol=0.54

Number of moles of Acetic acid =50/60g/mol​=0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water =1.4/2.74​=0.51

       mole fraction of Ethanol =0.54/2.74​=0.197

       mole fraction of acetic acid =0.8/2.74​=0.291

hope this helps uh dear :)

pls mark as brainliest..........

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