Question

A solution contains 25% of water, 25% of ethanol and 50% of acetic acid by mass. Calculate the mole fraction of each component.

Answer 1

Answer:

Let the mass of solution is 100g

Then, mass of H

2

O=25g

mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water =

18g/mol

25g

=1.4

Number of moles of ethanol =

46g/mol

25g

=0.54

Number of moles of Acetic acid =

60g/mol

50g

=0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water =

2.74

1.4

=0.51

mole fraction of Ethanol =

2.74

0.54

=0.197

mole fraction of acetic acid =

2.74

0.8

=0.291

Answer 2

Answer:

marko nhi pata apko pta ha