Question

A solution contains 3.5 g of a non volatile solute in 125 g of H2O and it boils at 373.52 K(Tb) . Calculate the molar mass of the solute (M2).[ Given, Kb = 0.52 Kg/mol , Tb° = 373 K]

Answer 1

Answer:

we have the formula :

  Tb - Tb° = kb * m

  where m is the molality

 

molality = mass * 1000/( molar mass * mass of water)

m = 3.5 *1000/(M * 125)

m = 28/M

  where M is the molar mass of the solute

putting the values in the equation :

373.52 - 373 = 0.52 * (28/M)

0.52 = 0.52 * 28/M

M= 28

Explanation:

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