A solution contains 3.5 g of a non volatile solute in 125 g of H2O and it boils at 373.52 K(Tb) . Calculate the molar mass of the solute (M2).[ Given, Kb = 0.52 Kg/mol , Tb° = 373 K]
Answers
Answered by
2
Answer:
we have the formula :
Tb - Tb° = kb * m
where m is the molality
molality = mass * 1000/( molar mass * mass of water)
m = 3.5 *1000/(M * 125)
m = 28/M
where M is the molar mass of the solute
putting the values in the equation :
373.52 - 373 = 0.52 * (28/M)
0.52 = 0.52 * 28/M
M= 28
Explanation:
mark me as brainlist
Similar questions