Question

a solution contains 30 gram of sugar dissolves in 270 gram of water calculate the concentration of in terms in terms of mass by mass percentage of the solution​

Answer 1

Provided that:

• Sugar = 30 g as solute
• Water = 270 g as solvent

To calculate:

• The concentration in the terms of mass by mass percentage of the solution.

Solution:

• The concentration in the terms of mass by mass percentage of the solution = 10 %

Using concept:

• Mass by mass percentage formula to calculate the concentration of the solution.

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{Mass \: \% \: = \dfrac{Mass_{solute}}{Mass_{solution}} \times 100 \: \%}}}}}}$

Knowledge required:

• "Solute" is present in "less quantity."

• "Solvent" is present is "excess quantity."

• "Solution" consists of two components that are "solute and solvent."

• The component of the solution that dissolves the other component in it is called the "solvent."

• The component of the solution that is dissolved in the solvent is called "solute."

Required solution:

~ Firstly let us calculate the mass of the solution by using suitable formula!

We know that solution is made up of two components that are solute and solvent.

Therefore,

=> Solution = solute + solvent

• ${\small{\underline{\boxed{\pmb{\sf{\red{Solution \: = Solute \: + Solvent}}}}}}}$

${\sf{:\implies Solution \: = Solute \: + Solvent}}$

${\sf{:\implies Solution \: = 30 + 270}}$

${\sf{:\implies Solution \: = 300 \: g}}$

${\pmb{\sf{\dag \: Henceforth, \: founded!}}}$

~ Now by using mass by mass percentage formula of concentration let us solve this question!

${\small{\underline{\boxed{\pmb{\sf{\red{Mass \: \% \: = \dfrac{Mass_{solute}}{Mass_{solution}} \times 100 \: \%}}}}}}}$

${\sf{:\implies Mass \: \% \: = \dfrac{Mass_{solute}}{Mass_{solution}} \times 100 \: \%}}$

${\sf{:\implies Mass \: \% \: = \dfrac{30}{300} \times 100 \: \%}}$

${\sf{:\implies Mass \: \% \: = \dfrac{3\not{0}}{30\not{0}} \times 100 \: \%}}$

${\sf{:\implies Mass \: \% \: = \dfrac{3}{30} \times 100 \: \%}}$

${\sf{:\implies Mass \: \% \: = \dfrac{300}{30} \: \%}}$

${\sf{:\implies Mass \: \% \: = \dfrac{30\not{0}}{3\not{0}} \: \%}}$

${\sf{:\implies Mass \: \% \: = \dfrac{30}{3} \: \%}}$

${\sf{:\implies Mass \: \% \: = \cancel{\dfrac{30}{3}} \: \%}}$

${\sf{:\implies Mass \: \% \: = 10 \: \%}}$

${\pmb{\sf{\dag \: Henceforth, \: solved!}}}$

Henceforth, mass by mass percentage in concentration = 10 %