Question

A solution contains 30g of glucose, 20g of sugar in 500ml of water. calculate the mass per cent of glucose and sugar (density of water=1g/ml). ​

Answer 1

Answer:

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Answer 2

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$\mathrm{(a) \: mass \: of \: glucose \: present \: in \: the \: solution = 30 \: g}$

$\mathrm{(b) \: mass \: of \: sugar \: present \: in \: the \: solution = 20 \: g}$

$\mathrm{(c) \: mass \: of \: water = 500 \: g}$

$\: \: \: \mathrm{total \: mass \: of \: the \: solution = (30 + 20 + 500)g}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathrm{ = 550g}$

$\mathrm{(a) \: mass \: \% \: of \: the \: glucose = \frac{mass \: of \: glucose}{total \: mass \: of \: solution} \times 100}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathrm{ = \frac{30}{550} \times 100}$

$\: \: \: \: \: \: \: \mathrm{mass \: \% \: of \:glucose = 5.45\%}$

$\mathrm{(b) \: mass \: \%\: of \: sugar = \frac{mass \: of \: sugar}{total \: mass \: of \: solution} \times 100}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathrm{ = \frac{20}{550} \times 100}$

$\: \: \: \: \: \mathrm{mass \% \: of \: sugar = 3.63\%}$