a solution contains 32 g of glucose in 410 gram of water calculate the concentration in terms of mass by mass percentage of the solution
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0
Answer:
MASS (SOLUTE) =40 GRAM
MASS (SOLVENT) =320 gram
MASS(SOLUTION =MASS (solute) +MASS
SOLVENT=40 GRAM +320 grams
mass% (solutions = MASS (SOLUTE) / MASS
SOLVENT x100 =460/30 100
11.1%
Answered by
2
Answer:
Mass of Solvent (water) - 410g
Mass of Solute (glucose) - 32g
Mass of Solution = Mass of Solute + Mass of solvent
→ 32 + 410 = 442g
→ Mass% (solution) = [Mass (Solute) / Mass (solvent) × 100
= × 100
= 7.80%
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