Question

A solution contains 320 g of methyl alcohol (CH3OH) and 540 g of water. The mole fraction of methyl alcohol in the solution is​

Answer 1

Answer:

see below

Explanation:

First, we convert the masses of the compounds to their mole quantities.

320 grams of methyl alcohol ( methanol ) is,

= \frac{320}{32} = 10 \ mol=

32

320

=10 mol

Similarly, 540 grams of water is,

= \frac{540}{18} = 30 \ mol=

18

540

=30 mol

Hence, the total molar mass of the solution is,

= 30 + 10 = 40 \ mol=30+10=40 mol

Hence, the mole fraction of methyl alcohol is,

x_{CH_3OH} = \frac{10 \ mol}{40 \ mol} = 0.25x

CH

3

OH

=

40 mol

10 mol

=0.25

Which gives us the answer.

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Answer 2

The mole fraction of methyl alcohol in the solution is 0.25.

GIVEN

Mass of Methyl alcohol = 320 grams

Mass of Water = 540 grams

TO FIND

Mole fraction of Methyl alcohol

SOLUTION

We can simply solve the above problem as follows;

Given mass of Methyl Alcohol = 320 grams

Molar mass of Methyl Alcohol = 32 g/mol

Moles of Methy alcohol = 320/32 = 10 moles.

Mass of water = 540 grams

Molar mass of water = 18 grams

Moles of Water in the solution = 540/18 = 30 moles.

Now,

Total number of moles in the solution = 30 + 10 = 40 moles.

We know that,

Mole fraction Methyl alcohol in the solution = Moles of methyl alcohol/Total number of moles of solution.

Putting the values in the above formula we get;

= 10/40

= 0.25

Hence, The mole fraction of methyl alcohol in the solution is 0.25.

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