Question

A solution contains 4 g of NaOH and 16.2 g of water.The mole fraction of the solute is
1 point
0.1
0.01
0.2
0.02

Answer 1

Answer:

0.1

Explanation:

moles of NaOH = (4)/40 = 0.1 mole

moles of H2O = 16.2 ÷ 18 = 0.9 mole

mole fraction of NaOH = (0.1) ÷ (01.+0.9)

mole fraction of NaOH = 0.1/1 = 0.1

Answer 2

Mole fraction of solute is 0.1.

Given - Mass of solute and solvent

Find - Mole fraction of solute

Solution - Mole fraction of solute = number of moles of solute/number of moles in solution

Number of moles = mass/molar mass

Molar mass of solute = 40 g/mol

Molar mass of water = 18 g/mol

Number of moles of solute = 4/40

Number of moles of solute = 0.1

Number of moles of solvent = 16.2/18

Number of moles of solvent = 0.9

Total number of moles = 0.1 + 0.9

Total number of moles = 1

Mole fraction = 0.1/1

Mole fraction = 0.1

Hence, the mole fraction is 0.1.

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