a solution contains 40% alcohol by volume.how much alcohol should be added to the solution of 100ml to make concentration of alcohol as 50%
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let the amount of alcohol added to make concentration of alcohol as 50% be x initial amount of alcohol = 40
40 + x = 1/2(100 + x)
80 + 2x = 100 + x
2x - x = 100 - 80
x = 20
40 + x = 1/2(100 + x)
80 + 2x = 100 + x
2x - x = 100 - 80
x = 20
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