Question

a solution contains 40 g common salt in 300 g water. claculate the concentration (mass/mass) of the solution in percentage.(please show the proper division) as soon as possible​

Answer 1

Answer:

11.76 %

Explanation:

As per the provided information in the given question, we have :

• Mass of solute [Common salt] = 40 g
• Mass of solvent [Water] = 300 g

We have to calculate the concentration of the solution in percentage.

$\longrightarrow\boxed{\bf{Concentration_{(Solution)} = \dfrac{Mass_{(Solute)}}{Mass_{(Solution)}} \times 100 }}$

Here,

→ Mass of Solution = Mass of Solute + Mass of Solvent

→ Mass of Solution = 40 g + 300 g

→ Mass of Solution = 340 g

Now, substitute the values.

$\longrightarrow\sf{Concentration_{(Solution)} = \dfrac{40}{340} \times 100 }$

$\longrightarrow\sf{Concentration_{(Solution)} = \dfrac{40}{34} \times 10 }$

$\longrightarrow\sf{Concentration_{(Solution)} =\cancel{ \dfrac{400}{34} }}$

$\longrightarrow\sf{Concentration_{(Solution)} =\cancel{ \dfrac{200}{17} }}$

$\longrightarrow\underline{\boxed{\sf {\blue{ Concentration_{(Solution)} = 11.76 \; \%}}}}$

Therefore, concentration of the solution is 11.76%.

Answer 2

Answer:

Given :-

• A solution contains 40 g of common salt in 300 g of water.

To Find :-

• What is the concentration of the solution in percentage of mass.

Formula Used :-

$\clubsuit$ Concentration of Solution in Percentage Formula :

$\small \bigstar \: \: \sf\boxed{\bold{Concentration\%_{(Solution)} =\: \bigg\lgroup \dfrac{Mass_{(Solute)}}{Mass_{(Solution)}} \times 100\bigg\rgroup \%}}\: \: \: \bigstar$

Solution :-

First, we have to find the mass of solution :

Given :

• Mass of Solute of Common Salt = 40 g
• Mass of Solvent Solvent of Water = 300 g

According to the question by using the formula we get,

$\footnotesize \implies \sf\bold{\underline{Mass_{(Solution)} =\: Mass\: Of\: Solute_{(Common\: Salt)} + Mass\: Of\: Solvent_{(Water)}}}$

$\implies \sf Mass_{(Solution)} =\: 40\:g + 300\: g$

$\implies \sf\bold{Mass_{(Solution)} =\: 340\: g}$

Hence, the mass of solution is 340 g .

Now, we have to find the concentration of the solution in percentage of mass :

Given :

• Mass of Solution = 340 g
• Mass of Solute = 40 g

According to the question by using the formula we get,

$\footnotesize \implies \sf\bold{\underline{\underline{Concentration\%\: (m/m)_{(Solution)} =\: \bigg\lgroup \dfrac{Mass_{(Solute)}\: in\: g}{Mass_{(Solution)}\: in\: g} \times 100\bigg\rgroup \%}}}$

$\implies \sf Concentration\%_{(Solution)} =\: \bigg\lgroup \dfrac{40}{340} \times 100\bigg\rgroup \%$

$\implies \sf Concentration\%_{(Solution)} =\: \bigg\lgroup \dfrac{40 \times 100}{340}\bigg\rgroup \%$

$\implies \sf Concentration\%_{(Solution)} =\: \bigg\lgroup \dfrac{400\cancel{0}}{34\cancel{0}}\bigg\rgroup \%$

$\implies \sf Concentration\%_{(Solution)} =\: \bigg\lgroup \dfrac{400}{34}\bigg\rgroup \%$

$\small \implies \sf\bold{Concentration\%_{(Solution)} =\: 11.76\%(m/m)}$

$\therefore$ The concentration (mass/mass) of the solution in percentage is 11.76% .