A solution contains 40 gm of salt in 320 of water. Calculate
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Answered by
2
mass of salt= 40g
mass of the water= 320g
total mass of the solution= mass of solute + mass of solvent =
=40g + 320 g= 360 g
:mass by mass precentage of the solution= mass of the solute *100 /mass of the solution
= 40*100/360
= 11.111% (approx.)
*hope it helps you*
mass of the water= 320g
total mass of the solution= mass of solute + mass of solvent =
=40g + 320 g= 360 g
:mass by mass precentage of the solution= mass of the solute *100 /mass of the solution
= 40*100/360
= 11.111% (approx.)
*hope it helps you*
Answered by
1
Hey there!
Given,
Mass (solute) = 40 gram
Mass (solvent) = 320 gram
Mass (solution) = Mass (solute) + Mass (solvent)
= 40 gram + 320 gram
= 360 gram
∴ Mass % (solution) = [ Mass (solute)/Mass (solvent)] × 100
= [40/360] × 100
= 11.1 %
Hope It Helps You!
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