Physics, asked by rohith2908, 7 months ago

A solution contains 40g of sugar in 450g of water.calculate the concentration of solution in terms of mass by mass percent of the solution​

Answers

Answered by nupurswain393
21

Answer:mass percent = 8.16 %

Explanation: mass percent =

Mass of solute / mass of solution × 100

{ Don't get confused... It's mass of solution and not only the solvent. Here, In this case; water is the solvent but the solution would be water + sugar. So beware, mass of the solution would be = 450g + 40g= 490g}

Therefore,

Mass percent = 40/490 × 100= 8.16 %

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Answered by Anonymous
39

Given that, a solution contains 40g of sugar in 450g of water.

In a solution that dissolved is the solute and that does dissolving is solvent. Here, sugar is solute and water is solvent.

Mixture of both solute and solvent is know as solution.

We have to find the mass percent of the solution.

Mass of solute = 40 g

Mass of solute = 40 gMass of solvent = 450 g

Mass of solution = Mass of solute + Mass of solvent

= (40 + 450) g

= 490 g

Now,

Mass percent is defined as the ratio of mass of solute with respect to mass of solution, multiplied by 100% i.e.

Mass% = (Mass of solute)/(Mass of solution) × 100

Substitute the known values in the above formula,

= 40/490 × 100

= 0.0816 × 100

= 8.16%

Therefore, the mass percent of the solution is 8.16%.

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