Chemistry, asked by dksfasteners, 1 year ago

A solution contains 410.3 g of H2SO4 per litre of solution at 20 ° C .
If it's density is 1.0243 gm /cm³ . What will be it's molarity and molality.
( Pls give step wise procedure for molality )

Answers

Answered by malavikabala012003
0

no. of moles of H₂SO₄ = 410.3/ 98

=4.18moles

molarity= 4.18/1

=4.18MOLAR

molality= (1000×Molarity)/(1000×density-Molarity ×Gram molar weight)

= (1000×4.18)/(1000×1.0243)-(4.18×98)

=4180/614.6

=6.8 molal

Similar questions