A solution contains 410.3 g of H2SO4 per litre of solution at 20 ° C .
If it's density is 1.0243 gm /cm³ . What will be it's molarity and molality.
( Pls give step wise procedure for molality )
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no. of moles of H₂SO₄ = 410.3/ 98
=4.18moles
molarity= 4.18/1
=4.18MOLAR
molality= (1000×Molarity)/(1000×density-Molarity ×Gram molar weight)
= (1000×4.18)/(1000×1.0243)-(4.18×98)
=4180/614.6
=6.8 molal
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