Question

a solution contains 50 ml of alcohol mixed with 150 ml of water calculate the concentration of the solution...​

Answer 1

Given :-

a solution contains 50 ml of alcohol mixed with 150 ml of water calculate the concentration of the solution.

Solution :-

This solution contains a liquid solute ( alcohol ) mixed with a liquid solvent ( water ) , so we have to calculate the concentration of this solution in terms of volume percentage of solute ( alcohol ). Now, we know that :

→ Concentration of solution

$\large\sf{\frac{ Volume \: of \: solute}{Volume \: of \: solution }\sf\large\times 100}$

Here, Volume of solute ( alcohol ) = $\sf{50 ml}$

And, Volume of solvent ( water ) = $\sf{150 ml}$

So,

Volume of solution → volume of solute + volume of solvent

⇒ $\sf{50 + 150}$

⇒ $\sf{200 ml}$

Now, putting these values of ‘ volume of solute ’ and ‘ volume of solution ’ in the above formula we get :

Concentration of solution → $\large\sf{\frac{50}{200} \large\sf\times 100}$

⇒ $\large\sf\frac{50}{2}$

⇒ 25 percent ( by volume )

Thus, the concentration of this alcohol solution is 25 percent or that it is a 25 % alcohol solution ( by volume ).