Question

A solution contains 50 ml of alcohol mixed with 150 ml of water. Calculate the concentration of the solution.​

Answer 1

Answer:

Volume of solute= 50ml

Volume of solvent= 150ml

∴ Total volume= 150+50=200ml

Concentration=  

Volume of solution

Volume of solute

​  

×100

                       =  

200

50

​  

×100

                       =25%

Answer 2

Given :-

• Volume of solute = 50 ml
• Volume of solvent = 150 ml

To find :-

• Concentration of thebsolution

Formula used :

• Concentration of solutions = $\frac{volume \: of \: solute}{volume \: of \: solution } \times 100$

Solution :-

Concentration of solution = $\frac{volume \: of \: solute}{volume \: of \: solution } \times 100$

Volume of solute = 50 ml

Volume of solvent = 150 ml

Volume of solution = volume of solute + volume of solvent

$=> ( 50 + 150 ) ml \\ => 200 ml \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

By putting the value of volume of solute and the volume of solution,

Concentration of the solution,

$=> \frac{50}{200} \times 100 \: \: \: \\\ => \frac{1}{4} \times 100 \: \: \: \: \: \: \: \: \\ => \frac{100}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ => 25 \% \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

So, the concentration of the solute is 25 % .