A solution contains 50 ml of alcohol mixed with 150 ml of water . calculate the concentration of this solution .
9th class chemistry .
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Answered by
29
concentration of solution = volume of solute / volume of solution ×100
volume of solute alcohol is 50 ml
volume of solvent water is 150 ml
volume of solution = volume of solute + volume of solvent
50 + 150
= 200 ml
put this value in the above formula .
concentration of solution = 50 / 200 × 100
= 50 / 2
= 25% ( by volume )
volume of solute alcohol is 50 ml
volume of solvent water is 150 ml
volume of solution = volume of solute + volume of solvent
50 + 150
= 200 ml
put this value in the above formula .
concentration of solution = 50 / 200 × 100
= 50 / 2
= 25% ( by volume )
manny3:
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Answered by
10
Answer:
Mass of solute (alcohal)=50ml
Mass of solvent (water)=150ml
...........solution =Mass of solute-Mass of solvent
=50+150
=200ml
concentration of solution=Mass of solute/Mass of solvent×100
=50/200×100
=25%
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