Question

A solution contains 50g of common salt in 150g of water .mas percentage of solution is​

Answer 1

Correct Question  -

A solution contains 50 grams of common salt dissolved in 150 grams of water .

Find the  mass by mass percentage of the concentration of the salt in the solution .

Solution -

In the above question, the following information is given -

A solution contains 50 grams of common salt dissolved in 150 grams of water .

We have to find the mass by mass percentage of the concentration of the salt in the solution .

We can find that the given mass of common salt dissolved in the saline solution is 50 grams .

The mass of water provided is 150 grams.

Here, the common salt is the solute and water is the solvent .

Mass Of the solution = Mass Of Solute + Mass Of Solvent

= 50 grams + 150 grams

= 200 grams.

So, the mass of the required solution is 150 grams.

Mass by mass percentage of the concentration of the salt in the solution :

$\dfrac{ Mass \ Of \ Solute }{ Mass \ Of \ Solution } \times 100 \% \\ \\ => \dfrac{50}{200} \times 100 \% \\ \\ => 25 \%$

Hence the required  mass by mass percentage of the concentration of the salt in the solution is 25 %.

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Answer 2

Answer:

The mass of the common salt (solute) = 50 g   (given)

The mass of water = 150 g   (given)

So,

The total mass of solution = mass of salt + mass of water

so,

mass of solution = 50 g + 150 g

                           = 200 g

Now,

To be found :

The concentration of the solution

We know that,

$concentration \: of \: solution = \frac{mass \: of \: solute}{mass \: of \: solution} \: 100 \times$

$The concentration of the solution = \frac{50}{200} 100 \times$

$The concentration of the solution = 25%$

∴ The concentration of solution = 25%