Chemistry, asked by Mandy1905, 1 year ago

A solution contains 60 gram of sugar in 300 gram of water calculate the concentration in terms of mass by mass percentage of the solution concentration in terms of mass by volume percentage of the solutionr

Answers

Answered by BarrettArcher
11

Answer : The concentration in terms of mass by mass % = 16.667 %

The concentration in terms of mass by volume % = 17.736 %

Solution : Given,

Mass of sugar = 60 gram

Mass of water = 300 gram

Density of sugar = 1.59 g/ml

Density of water = 0.9982 g/ml

  • Mass by Mass % Calculation :

We have to calculate the concentration in terms of mass by mass %.

(Sugar = solute and water = solvent)

Mass of solute = 60 gram

Mass of solvent = 300 gram

Mass of solution = Mass of solute + Mass of solvent = 60 + 300 = 360 gram

\text{ Concentration mass by mass }\% =\frac{\text{ Mass of solute}}{\text{ Mass of solution}}\times 100=\frac{60g}{360g}\times 100=16.666\%

Therefore, the concentration in terms of mass by mass % = 16.667 %

  • Mass by Volume % Calculation :

First we have to calculate the volume of sugar and water.

\text{ Volume of water}=\frac{\text{ Mass of water}}{\text{ Density of water}}=\frac{300g}{0.9982g/ml}=300.54ml

\text{ Volume of Sugar}=\frac{\text{ Mass of sugar}}{\text{ Density of sugar}}=\frac{60g}{1.59g/ml}=37.74ml

The Volume of solution = Volume of water + Volume of sugar = 300.54 + 37.74 = 338.28 ml

Now we have to calculate the concentration in terms of mass by volume %.

\text{ Concentration mass by volume }\% =\frac{\text{ Mass of solute}}{\text{ Volume of solution}}\times 100=\frac{60g}{338.28g}\times 100=17.736\%

Therefore, the concentration in terms of mass by volume % = 17.736 %


Answered by geetapinkitanwar
3

Answer:

13.04

Explanation:

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