Chemistry, asked by Rudraksh243, 10 months ago

a solution contains a moxture of na2co3 and naoh. using phenolphtelein as indicator,20ml of the mixture required 15ml of 1.0N hcl for the endpoint. with methyl orange as indicator,20ml of the solution required 20ml of the same hcl for the endpoint.
find:-1. Mass of naoh present in on litre of the solution
2. Mass of na2co3 present in one litre of the solution
answer this ill mark you brainliest.✌​

Answers

Answered by satishkanojia50
0

Answer:

Meq. of HCl for 35 mL mixture using phenolphthalein indicator =19.5×0.005=0.0975

∴ Meq. of NaOH +

2

1

Meq. of Na

2

CO

3

=0.0975 ...(i)

Now, meq. of HCl used for 25 mL mixture using methyl orange as indicator =25.9×0.005=0.1295...(ii)

∴ By eqs. (i) and (ii), we get meq. of NaOH =0.0655

40

w

×1000=0.0655

∴ Mass of NaOH= 2.62×10

−3

g/25

Strength of NaOH = 0.1048g/litre

and answer is 1.

Also,

Meq. of Na

2

CO

3

=0.064

106/2

w

×1000=0.064

Mass of Na

2

CO

3

=3.392×10

−3

g/25 mL

Strength of Na

2

CO

3

=0.1357g/litre

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