A solution contains Mg2+ions, Fe2+ ions and Cu2+ ions. On passing an electric current through this solution which ions will be the first to be discharged at the cathode. Write the equation for the cathode reaction. no spamming
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Cu2+ ions will be deposited at cathode.
Cu2+(aq) + 2e- --> Cu(s) ( reduction )
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Answer: Cu2+
Cu2++2e=Cu
Explanation:
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