Question

A solution has 1.2046*10^23 hcl molecule in 1 l of the solution.The strength of the solution is

Answer 1

Molecules of HCl = 1.2046 x 10^23

Moles of HCl = Given molecules/Molar molecules = 1.2046 x 10^23 / 6.02 x 10^23 = 0.2 mol

Volume of solution = 1L

Molarity = no. of moles of HCl/Volume of solution in L = 0.2/1 = 0.2 mol/L

Strength = Molarity x Molar mass of HCl = 0.2 x 36.5 = 7.3 g/L