A solution has 1:4 mlar ratio of pentane and
hexane. The vapour pressure of pure hydrocarbons at 20°C a 440 mmhg for pentane
and 120 mm of Hg for hexane.the mole fraction of pentane in vapour phase would be
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answer- Mole fraction of pentane solution=
1+4
1
=
5
1
Mole fraction of hexane solution=
1+4
4
=
5
4
Total pressure of solution, P
S
=X
P
P
P
O
+X
H
P
H
O
=
5
1
×440 mm Hg+
5
4
×120 mm Hg
=184 mm Hg
∴ The fraction of pentane in the vapour phase
=
P
S
X
P
P
P
O
=
184
88
=0.478 .
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