Question

A solution has 46% w/w ethyle alcohol find the mole fraction of C2H5OH and water​

Answer 1

Answer:

0.25

Explanation:

If a solution has 46% W/W ethyl alcohol in water, what is the mile fraction of ethyl alcohol (C2H5OH)?

46 g of ethyl alcohol is present in 100 g of solution.

Step 1: Find molar masses of solute and solvent.

Molar mass of C₂H₅OH = 2C + 6H + 1O = 2x12 + 6x1 + 1x16 = 46 g

Molar mass of H₂O = 2H + 1O = 2x1 + 1x16 = 18 g

Step 2: Find number of moles.

Moles of substance = Given mass / Molar mass

Moles of C₂H₅OH = 46 g / 46 g = 1 mole

Moles of H₂O = 54 g / 18 g = 3 moles

Step 3: Divide number of moles of solute by total number of moles in solution.

Mole fraction of C₂H₅OH = 1 / (3+1) = 1 / 4 = 0.25

The mole fraction of 46% w/w ethyl alcohol in water solution is 0.25.