Question

A solution has been prepared by addying 60g of methanol to 120g of water calculate
- the mole fraction of methanol in solution.​

Answer 1

mass of methanol=60g

molar mass=32

$molesb = \frac{60}{32} = 1.87$

mass of water=120

molar mass=18

$moles \: a = \frac{120}{18} = 6.66$

$x \: m = \frac{nb}{na + nb} = \frac{1.87}{8.53} = 0.22$

I hope this helps ( ╹▽╹ )

Answer 2

Explanation:

Given conditions ⇒

Mass of the Methanol = 60 g.

Molar mass of the Methanol = 32 g/mole.

∵ No. of moles of Methanol =

Molar Mass

Mass

∴ No. of moles = 60/32

= 1.875 mole.

Mass of the Water = 120 g.

Molar mass of the water = 18 g/mole.

∴ No. of moles of Water =

Molar mass

Mass

.

= 120/18

= 6.67 mole.